scanmanmi
Member
Watts is amps x volts. How can watts be measured when there is no completed circuit. I understand a circuit with a 50 ohm resistor but the circuit becomes open with a normal antenna. If I'm reading 50 watts where are my amps?
Watts is amps x volts. How can watts be measured when there is no completed circuit. I understand a circuit with a 50 ohm resistor but the circuit becomes open with a normal antenna. If I'm reading 50 watts where are my amps?
To DC that appears an open. However, when applying AC at the resonate frequency, the impedance will be near 50 ohms.
Watts is amps x volts. How can watts be measured when there is no completed circuit. I understand a circuit with a 50 ohm resistor but the circuit becomes open with a normal antenna. If I'm reading 50 watts where are my amps?
Watts is amps x volts. How can watts be measured when there is no completed circuit. I understand a circuit with a 50 ohm resistor but the circuit becomes open with a normal antenna.
So, this thread made me think of a question (stupidity level = 4)
Is there a difference between Watts used by the radio from the
power supply and the amount of watts transmitted out of the antenna?
Watts up? (Sorry—couldn't resist...)
So, this thread made me think of a question (stupidity level = 4)
Is there a difference between Watts used by the radio from the
power supply and the amount of watts transmitted out of the antenna?
Where do the 6.25 x 10^18 electrons travel to?50W with 50 Ohm impedance is equal to 1A
Where do the 6.25 x 10^18 electrons travel to?
It's high frequency AC. They go half a wavelength forwards and then come back the same half wavelength but they dissipate their energy on the way.