Right - lets talk you through this thing - get the schematic in front of you.
+13.8 V DC from the main power supply is applied to the centre tap on the primary of the transformer via a bit of filtering, C1, C2 and L1.
The two transistors Q1 and Q2 along with R1/C3 and R2/C4 form an astable (unstable?) multivibrator - one transistor is conducting heavily while the other one is turned off hard, but it can't stay in this state. The highish voltage on the collector of the "off" transistor is conducted through the R/C combination the base of the other transistor turning it on and so on continuously at a frequency determined by the values of R1 and C3/R2 and C4 the transistors flip and flop backwards and forwards.
Current therefore flows sequentially through the primary of the transformer - 3 to 1 then 3 to 2 and back and forth. Therefore a square wave voltage at some frequency (which I have not measured or found) comes out of the three secondaries. The top pair I guess are two windings in series and give out 28volts peak to peak and the other bigger winding 62volts peak to peak.
Then follows three pretty standard voltage regulators - not much current involved so no massive heatsinks. The diode Q1 conducts on the positive half cycle and charges the capacitor C7 to +30volts, the other two diodes D3 and D6 conduct on negative half cycles and charge capacitors C11 to -31volts and C16 to -10volts. The zener diodes at the base of all three transistors are fed through their resistors from the collector voltage and these zeners stabilise the base voltage of their transistors.
By normal emitter follower action, the emitter voltages are about 0.6volts less than the zener voltage. There are some magic bits of wire in there that have different voltages on one end than they do at the other, but we'll take that with a grain of salt!
So - the emitter of Q5 is 0.6v lower than it's base, -8.2v + 0.6v = -7.6volts, Q3 base 24volts, emitter 23.6 volts and a bit less through the R7 and a bit of filtering = 22.0v, and Q4 base -12v, emitter plus 0.6v = -11.4volts and another bit of filtering = -11.0volts.
The 9v comes in and goes out again without any circuitry in the way.
So there you are, treat it like four bits of separate circuit and you be able to find where the problem is.
Have fun - persevere!
