pro 97 can't enter 2738 tgid

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Voyager

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rb30533 said:
every time i try to enter 2738 tgid it enter 2736, anyone else have this problem.

rb30533

As I said on email:

2736 is the base ID if this is a 3600 system. 2738 is 2736 with a status
bit of 2. If this is a 9600 system, I don't know what to tell you.

Joe M.

P.S. Of course 2738 is a valid TG ID - it just has status bits encoded if 3600, or perfectly normal if 9600. Valid TGs go from the basement (0) to 65535.
 

loumaag

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Voyager said:
2736 is the base ID if this is a 3600 system. 2738 is 2736 with a status bit of 2. If this is a 9600 system, I don't know what to tell you.
Since he is working with a Pro-97, APCO systems are not a concern, he can't monitor therm anyway. All GRE built scanners (to the best of my knowledge) pay no attention to the status bits and report the base TG ID for Motorola Type II systems.
 

n4yek

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rb30533 said:
every time i try to enter 2738 tgid it enter 2736, anyone else have this problem.

rb30533

The Pro 97 is like the Pro 95, it ignores the statis bit which you are trying
to enter when you try 2738. The radio will enter it as 2736 and this isn't
going to cause you to miss anything. If there is an emergency transmited
that takes place on 2738 you will hear it on 2736.
This applys to ALL status bits (there are 15 of them) and they would
all revert back to the 2736 ID number if you tried to enter them.

Look at this link and go down to 'System II Special Status Bits',
this will show you what each status bit is for. Each will be heard
on the original ID when trying to use the Pro 97.

http://www.radioreference.com/modules.php?name=Content&pa=showpage&pid=1

Danny
N4YEK
 

DonS

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n4yek said:
This applys to ALL status bits (there are 15 of them)

Nitpick...

There are 4 status bits. There are 16 different combinations (15 of which have at least one bit set).
 

Voyager

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DonS said:
n4yek said:
This applys to ALL status bits (there are 15 of them)

Nitpick...

There are 4 status bits. There are 16 different combinations (15 of which have at least one bit set).

It depends if you are counting in decimal or binary. 8)

There are 15 decimal status bit IDs between the base IDs (16 IDs total per base ID). They are made up from the 4 binary TGID bits encoded in the datastream.

So, you're both right.

Joe M.
 
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