Project25_MASTR
Millennial Graying OBT Guy
You're contradicting Shannon's theorem. How much data can you send in a 3 kHz channel? Approx. 30 kbit/s using Trellis coded modulation. https://en.wikipedia.org/wiki/Modem#V.34.2F28.8.C2.A0kbit.2Fs_and_33.6.C2.A0kbit.2Fs
That's ignoring today's advances in audio codecs (re. CD quality vs lossy encoding).
Not really. You have to bring all of Hartley's, Shannon's, and Nyquists theorems and laws into play.
If you have a bandwidth of 3000 Hz, the Nyquist rate is 6000 baud (not to be confused with bps). Applying Hartley's law (which defines the number of definable bits per symbol) with a standard 4FSK modulation scheme, then 12,000 bps is the maximum throughput you can get. Now, if you go to something like 64QAM, that number increases by a factor of 6 (so the limit would be 72,000 bps). Then you have the Shannon-Hartley theorem which actually states the channel capacity is based upon the SNR (limit as you approach an SNR of 0 dB tells you the maximum amount of packet loss you can handle before you are under the noise floor).
Then you are starting to get into modulation indexes (which actually measure the deviation versus bandwidth or deviation versus data throughput)...