YesterdayMan
Newbie
- Joined
- Nov 10, 2024
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- 2
I thought I completely understood AM modulation since I learned about it in college 30 years ago, but now I have to question my understanding, since I've found several sources that explain the bandwidth of SSB transmission the same.
Please allow me to present an example that conveys my confusion:
A carrier signal of 20kHZ is used to transmit a 3kHZ sinewave. The receiver can reconstruct the sinewave from the amplitude of the carrier signal. Therefore, the bandwidth consists of only one frequency, 20kHZ. If we consider the 3kHZ sinewave that's being superimposed upon the carrier wave, we could say that in addition to the 20kHZ carrier wave, there is also a 3kHZ sinewave that rides upon the top of the carrier signal and a mirror image signal that's imposed upon the bottom. However, both the top and the bottom signals that are imposed upon the carrier frequency would be a 3kHZ sine wave. This 3kHZ sinewave, if it were transmitted with a higher frequency carrier wave, say 40kHZ, would have greater definition, but the same frequency, 3kHZ. The frequency of the transmitted signal is independent of the carrier frequency.
What I envision is 2 signals that could be drawn from the transmission. A 20kHZ carrier frequency, and the 3kHZ signal. There is nothing being transmitted at 10kHZ for instance. However, in the scenario I described above, if we were transmitting a 3kHZ signal on a 20kHZ carrier wave, using SSB, I believe the conventional wisdom is that the bandwidth would be 23kHZ. This doesn't make sense to me. We're not using 23kHZ of bandwidth. We're using one frequency only.
Can someone help me make sense of this?
Thank you,
Please allow me to present an example that conveys my confusion:
A carrier signal of 20kHZ is used to transmit a 3kHZ sinewave. The receiver can reconstruct the sinewave from the amplitude of the carrier signal. Therefore, the bandwidth consists of only one frequency, 20kHZ. If we consider the 3kHZ sinewave that's being superimposed upon the carrier wave, we could say that in addition to the 20kHZ carrier wave, there is also a 3kHZ sinewave that rides upon the top of the carrier signal and a mirror image signal that's imposed upon the bottom. However, both the top and the bottom signals that are imposed upon the carrier frequency would be a 3kHZ sine wave. This 3kHZ sinewave, if it were transmitted with a higher frequency carrier wave, say 40kHZ, would have greater definition, but the same frequency, 3kHZ. The frequency of the transmitted signal is independent of the carrier frequency.
What I envision is 2 signals that could be drawn from the transmission. A 20kHZ carrier frequency, and the 3kHZ signal. There is nothing being transmitted at 10kHZ for instance. However, in the scenario I described above, if we were transmitting a 3kHZ signal on a 20kHZ carrier wave, using SSB, I believe the conventional wisdom is that the bandwidth would be 23kHZ. This doesn't make sense to me. We're not using 23kHZ of bandwidth. We're using one frequency only.
Can someone help me make sense of this?
Thank you,