BillQuinn said:

how many trunking systems can be put in the scanner. 4,5???

Available memory - which means that it will depend on the type of trunking system, the number of talkgroups, the number of other objects.

Based on my formulae above, if you only put one talkgroup in each trunking system, and had no CONV, SRCH, or SWPR objects, you could have 168 Motorola or P25 trunking systems:

(<number of systems> x <10 blocks per system>) + (<number of systems> x <talkgroups per system> x <1 block per talkgroup>)

(168 x 10) + (168 x 1 x 1) = 1848.

If each Mot trunking system had 20 talkgroups, you could have 61 systems:

(61 x 10) + (61 x 20 x 1) = 1830

Trunking system: 10 blocks

Talkgroup: 1 block

Sum of all trunking systems and talkgroups must no greater than 1852 blocks (again, assuming no other objects).